Add new comment

Permalink In reply to by Anonymous (not verified)

correct me if I'm wrong but "y" is a variable, the d is supposed to represent a differential amount of "y" because that is an integral and usually they tell you what variable you integrate with respect to. In fact I believe that equation is a convolution between the function f and g which is essentially the operation you perform when applying a blurring function. That brings me to a question myself that is, why is the dy raised to the power of 2?

Filtered HTML

  • Web page addresses and email addresses turn into links automatically.
  • Allowed HTML tags: <a href hreflang> <em> <strong> <cite> <code> <ul type> <ol start type> <li> <dl> <dt> <dd>
  • Lines and paragraphs break automatically.